The memory address in the Interrupt Vector Table of an 8086 associated with INT13H should be:
13H * 4H = 4CH
But a book I was referring to says that:
The physical address of the memory location where address of the ISR is stored can be calculated by multiplying four to the type of interrupt and then converting it in hexadecimal.
According to them, physical Address of INT13H is
34H ( 13*4 = 52 )
I still think that 4CH is the address, and not 34H.