2

I'm finding the MOD operand is not working when I enter it in the BASIC prompt. This is how I write it out.

PRINT 1 * MOD(23)

?SN Error

I have looked into a reference guide and it is too broad on the MOD operand. On page 10 in the link.

TRS-80 Model 100 Reference

10

MOD is an operator, not a function.

Try ? 10 mod 9 and see yourself.

2

Several BASIC dialects have DIV and MOD operators, which return the quotient and remainder respectively from integer division. This is nearly equivalent to using / and % operators on integers in C. They are infix operators, even though their syntax is a keyword rather than a symbol.

Conversely, the / operator in most BASICs performs floating-point division and has no remainder counterpart.

A = 124
D = 34
Q = A DIV D
R = A MOD D
F = A / D
PRINT Q,R,F

yields

3    22    3.6471
1

For anyone unfamiliar with mathematics the answer is simple. After trying brute force I found that the format is sometimes confusingly different than pencil and paper.

Here it is.

print 124 MOD 34
22
  • 5
    Just out of curiosity, what did you think the meaning of a one-operand MOD function would be? – another-dave Apr 3 at 0:58
  • 3
    And why multiply it by one? – Bill Hileman Apr 3 at 13:15
  • Mathematicians use "mod" more has a notation indicating they're working with the integers modulo N rather than an operator. They'll write "5 = 12 mod 7" hence Travis' first guess. en.wikipedia.org/wiki/Modular_arithmetic covers this in more detail – George Phillips Sep 13 at 19:14

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